2^2x-33(2^x)=-32

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Solution for 2^2x-33(2^x)=-32 equation: 



2^2x-33(2^x)=-32

We move all terms to the left:

2^2x-33(2^x)-(-32)=0

We add all the numbers together, and all the variables

2^2x-332^x+32=0

We move all terms containing x to the left, all other terms to the right

2^2x-332^x=-32

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